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 Post subject: inequility problemPosted: Thu, 17 May 2012 16:34:32 UTC
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when the range of x determine by -ax^2+bx+4>=0 is (-1/3)<=x<=4 ;
then a=?,b=?

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 Post subject: Re: inequility problemPosted: Thu, 17 May 2012 16:47:44 UTC
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anik wrote:
when the range of x determine by -ax^2+bx+4>=0 is (-1/3)<=x<=4 ;
then a=?,b=?

What have you tried? Where is your work?

By the way, it is inequality, not inequility.

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 Post subject: Re: inequility problemPosted: Thu, 17 May 2012 17:02:59 UTC
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anik wrote:
when the range of x determine by -ax^2+bx+4>=0 is (-1/3)<=x<=4 ;

What do you get IF: -ax^2 + bx + 4 = 4 ?

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