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 Post subject: lateral areasPosted: Mon, 21 May 2012 17:01:27 UTC
 S.O.S. Newbie

Joined: Mon, 21 May 2012 16:48:20 UTC
Posts: 1
The ratio of the heights of two similar rectangular prisms is 2:3. What is the ratio of their lateral areas?

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 Post subject: Re: lateral areasPosted: Mon, 21 May 2012 18:16:19 UTC
 S.O.S. Oldtimer

Joined: Fri, 27 Jul 2007 10:17:26 UTC
Posts: 279
Location: Chandler, AZ, USA
Well, if the heights have a ratio of 2:3, what do you think the ratio of the lengths is? Or of the widths?

If you know the ratio of the one-dimensional measurements (such as height), what happens to the ratio of two-dimensional measurements (areas)?

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 Post subject: Re: lateral areasPosted: Mon, 21 May 2012 18:39:23 UTC
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Joined: Wed, 30 Mar 2005 04:25:14 UTC
Posts: 13971
Location: Austin, TX
alstat wrote:
Well, if the heights have a ratio of 2:3, what do you think the ratio of the lengths is? Or of the widths?

If you know the ratio of the one-dimensional measurements (such as height), what happens to the ratio of two-dimensional measurements (areas)?

The prisms are similar, so the ratios will be the same.

The ratio of the heights of two similar rectangular prisms is 2:3. What is the ratio of their lateral areas?

areas scale with the square of the linear dimensions.

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 Post subject: Re: lateral areasPosted: Tue, 22 May 2012 05:00:26 UTC
 S.O.S. Oldtimer

Joined: Fri, 27 Jul 2007 10:17:26 UTC
Posts: 279
Location: Chandler, AZ, USA
alstat wrote:
Well, if the heights have a ratio of 2:3, what do you think the ratio of the lengths is? Or of the widths?

If you know the ratio of the one-dimensional measurements (such as height), what happens to the ratio of two-dimensional measurements (areas)?

The prisms are similar, so the ratios will be the same.

The ratio of the heights of two similar rectangular prisms is 2:3. What is the ratio of their lateral areas?

areas scale with the square of the linear dimensions.

Nice answers, but I was asking the op. I was hoping he/she could answer them so that he/she could then answer the original question.

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