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 Post subject: What did I do wrong here? (2)Posted: Sat, 19 May 2012 16:58:46 UTC
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Question: Find the area of the following bounded region:
{ (x,y) | 1 ≤ x ≤ \sqrt{2} and 0 ≤ y ≤ ln(x + \sqrt{x^2 - 1} }

http://i1084.photobucket.com/albums/j40 ... MG007a.png
http://i1084.photobucket.com/albums/j40 ... MG007b.png

I get ln|1-1| near the end...

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 Post subject: Re: What did I do wrong here? (2)Posted: Sat, 19 May 2012 22:53:43 UTC
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Joined: Wed, 30 Mar 2005 04:25:14 UTC
Posts: 13973
Location: Austin, TX
A-R-Q wrote:
Question: Find the area of the following bounded region:
{ (x,y) | 1 ≤ x ≤ \sqrt{2} and 0 ≤ y ≤ ln(x + \sqrt{x^2 - 1} }

http://i1084.photobucket.com/albums/j40 ... MG007a.png
http://i1084.photobucket.com/albums/j40 ... MG007b.png

I get ln|1-1| near the end...

As an FYI, a lot of people will ignore posts that are hard to read (for example, I'm about 30/70 will/won't read ratio for things that I have to rewrite on my own to understand). If you want to be more likely to receive help you really should learn a little TeX, you're at 411 posts on a place where that is the standard.

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 Post subject: Re: What did I do wrong here? (2)Posted: Sun, 20 May 2012 09:31:35 UTC
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Joined: Mon, 29 Dec 2008 17:49:32 UTC
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A-R-Q wrote:
Question: Find the area of the following bounded region:
{ (x,y) | 1 ≤ x ≤ \sqrt{2} and 0 ≤ y ≤ ln(x + \sqrt{x^2 - 1} }

http://i1084.photobucket.com/albums/j40 ... MG007a.png
http://i1084.photobucket.com/albums/j40 ... MG007b.png

I get ln|1-1| near the end...

How did you get in the denominator instead of ?

Integrate by parts gives

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