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20carrolls
Math Cadet
Joined: 02 Nov 2009
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 Posted: Mon, 2 Nov 2009 20:16:57 UTC Post subject: Help |
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tnxs
Last edited by 20carrolls on Sat, 7 Nov 2009 13:13:50 UTC; edited 1 time in total |
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Shadow
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Location: Urbana, IL
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| Posted: Mon, 2 Nov 2009 23:40:56 UTC Post subject: |
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What have you tried?
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20carrolls
Math Cadet
Joined: 02 Nov 2009
Posts: 5
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| Posted: Wed, 4 Nov 2009 18:21:49 UTC Post subject: Binomial |
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HI,
I think I have to use the binomial on it. But first I have to get a new P value.
I think the one give is 1/4
Using bays theorem recalculate lets say P1 for the other brother
Then new P will be
I hope to get a new value
I am not sure may be I should do out all the 3 probability combinations and then add them up. |
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Shadow
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Joined: 30 Mar 2005
Posts: 4528
Location: Urbana, IL
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| Posted: Thu, 5 Nov 2009 05:43:31 UTC Post subject: Re: Binomial |
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| 20carrolls wrote: | HI,
I think I have to use the binomial on it. But first I have to get a new P value.
I think the one give is 1/4
Using bays theorem recalculate lets say P1 for the other brother
Then new P will be
I hope to get a new value
I am not sure may be I should do out all the 3 probability combinations and then add them up. |
Okay, there are two cases of three men with blood type X:
case I: two of the men are brothers
case II: none of the men are brothers
Consider them in turn. First choose the three men, then choose their blood types.
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20carrolls
Math Cadet
Joined: 02 Nov 2009
Posts: 5
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| Posted: Sat, 7 Nov 2009 12:55:35 UTC Post subject: Thank you |
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Hi I think I got it
12 combination at (1/4 * 1/4* 1/4)
above no brothers
8 combinations with brothers (1/4*1/4*3/4)
12*(1/4 * 1/4* 1/4) +8 (1/4*1/4*3/4)
I hope this is right
Anyhow thank you for your help |
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