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PostPosted: Wed, 29 Feb 2012 03:31:45 UTC 
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I have two fairly simple problems, and I know I could probably find the answers, but I want to understand the steps so I can complete future problems like these myself..If you know what you're doing please give me the steps and the answer would help too :)

Solve:
1.6^(4x)=102
2.log[base3]+log(4x-1)=5

Any help would be greatly appreciated!


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PostPosted: Wed, 29 Feb 2012 03:56:22 UTC 
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cayliejohnson369 wrote:
I have two fairly simple problems, and I know I could probably find the answers, but I want to understand the steps so I can complete future problems like these myself..If you know what you're doing please give me the steps and the answer would help too :)

Solve:
1.6^(4x)=102
2.log[base3]+log(4x-1)=5

Any help would be greatly appreciated!


If you want help on something you can do yourself you should at least post some work to show you care enough to try.

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PostPosted: Wed, 29 Feb 2012 04:00:51 UTC 
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That doesn't help me at all.
And I have tried to work on the problems..but I've come up with answers that I don't think are right plus I don't know the correct steps to take. How about only posting when you have an answer or steps..not to judge.


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PostPosted: Wed, 29 Feb 2012 04:06:04 UTC 
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cayliejohnson369 wrote:
That doesn't help me at all.
And I have tried to work on the problems..but I've come up with answers that I don't think are right plus I don't know the correct steps to take. How about only posting when you have an answer or steps..not to judge.


I'm not here to judge, but this board is to help people who are having trouble, not those who just don't want to do their own work. If you have some candidate answers you should provide them along with what you did go get them, this shows us you're at least invested enough in getting the answer to try for it yourself. Our time is also valuable, I'm just letting you know outright that you're wasting your time here if you expect answers without any effort on your part, most users will just ignore questions like this without letting the poster know that they could be using their time better elsewhere.

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PostPosted: Wed, 29 Feb 2012 18:01:32 UTC 
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following shadow thoughts, i will give you two clues:

solving a exponential equation, you will need, at the final, to use the inverse: a logarithm with the same basis

we have a^(x-y)=(a^x)/(a^y), so you use this property: Log (x/y) = Log x - Log y

if you have some scenarios of your work, show them and i help you finding your mistakes

Voxx


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PostPosted: Wed, 29 Feb 2012 18:24:23 UTC 
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cayliejohnson369 wrote:
1.6^(4x)=102

If a^x = b, then x = log(b) / log(a)

Since you're apparently unaware of this basic rule, then not much
can be done for you at a "help" site ; not a classroom.

If you were helping out at a help site for "bicycle riding",
what would you answer to: "where are the pedals"?

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PostPosted: Wed, 29 Feb 2012 19:04:57 UTC 
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cayliejohnson369 wrote:
I have two fairly simple problems, and I know I could probably find the answers, but I want to understand the steps so I can complete future problems like these myself..If you know what you're doing please give me the steps and the answer would help too :)

Solve:
1.6^(4x)=102
2.log[base3]+log(4x-1)=5

Any help would be greatly appreciated!


I don't understand what number 2 means..

\log_3+log(4x-1)=5

??


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