S.O.S. Mathematics CyberBoard Forum Index S.O.S. Mathematics CyberBoard
 
 FAQFAQ   SearchSearch   MemberlistMemberlist   UsergroupsUsergroups   RegisterRegister   ProfileProfile   Log in to check your private messagesLog in to check your private messages   Log inLog in 
[Resolved] Proofs

 
Post new topic   Reply to topic    S.O.S. Mathematics CyberBoard Forum Index -> Geometry and Trigonometry
View previous topic :: View next topic  
Author Message
integral0
Guest





PostPosted: Fri, 22 Aug 2003 21:58:27 UTC    Post subject: [Resolved] Proofs Reply with quote

When you are proving proofs in geometry, is it necessary to identify every single property along the way or can I skip over some small (non-important steps).

For example, I was doing a problem where I had an angle that was bisected. All of the rays of the angle (2) and the bisector (1) were then extended the other direction. Then the angles (4) were labeled 1,2,3,4. One had to prove the m<AOB = m<EOf (main large angles). So what I did was I said that the def. of bisector angle enables angles 3 and 4 to be congruent. Then I said that the vertical angles of 3 and 1, 2 and 4, and m<AOB and m<EOf were also equal because of the def. of vertical angles. So there was my proof.

However . . . the book had the substitution property involved and transitive property involved which are understandable but not really necessary (at least I think).

What do you have to say?


Last edited by integral0 on Sat, 13 Sep 2003 18:10:30 UTC; edited 1 time in total
Back to top
integral0
Guest





PostPosted: Sat, 23 Aug 2003 11:58:30 UTC    Post subject: i Reply with quote

odd . . . no one has responded Neutral
Back to top
integral0
Guest





PostPosted: Sat, 23 Aug 2003 20:42:59 UTC    Post subject: Reply with quote

thanks Soroban Smile
Back to top
jpmcgdogm
Guest





PostPosted: Sun, 24 Aug 2003 23:07:16 UTC    Post subject: Reply with quote

Transitive Property of Equality: if a = b and b = c, then a = c

Substitution Property of Equality: if a = b, then a can be substituted for b in any equation or inequality

vertical angles theorem
If two angles are vertical angles, then they have equal measures

I wouldn't say that your line of reasoning is wrong. Many times
while working with proofs in geometry there is usually more than one
way to get from your given to what you have to prove. I listed the properties
that you mentioned and then the vertical angles theorem so if you analyze them you may find that you can accomplish the same thing either way.

I hope that brings you some enlightenment.
Back to top
Display posts from previous:   
Post new topic   Reply to topic    S.O.S. Mathematics CyberBoard Forum Index -> Geometry and Trigonometry All times are UTC
Page 1 of 1

 
Jump to:  
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum


Contact Us | S.O.S. Mathematics Homepage
Privacy Statement | Search the "old" CyberBoard

users online during the last hour
Powered by phpBB © 2001, 2005-2010 phpBB Group.
Installation and all modifications: H. Knaust
Copyright © 1999-2010 MathMedics, LLC. All rights reserved.
Math Medics, LLC. - P.O. Box 12395 - El Paso TX 79913 - USA