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Alternating Series Test

 
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moonsenshi18
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PostPosted: Sat, 16 Apr 2005 14:28:53 UTC    Post subject: Alternating Series Test Reply with quote

Hi !
Just one more problem I need some help with!

How can I show that the summation n=1 to infinity of (-1)^n*n / 4^n is convergent by the Alternating Series Test?

I hope it is possible because I would like to estimate the sum by using the Alternating Series Estimation Theorem, which I can't use until I know that the given series is convergent by the A.S.T.

I m having trouble showing the limit as n approaches infinity of Bn (b sub-n) = 0.

Once again ideas by Monday would be wonderful!
I really do appreciate all the help so far Smile
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Kungsman
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PostPosted: Sat, 16 Apr 2005 14:43:59 UTC    Post subject: Reply with quote

Do you know what the alternating series test (Leibniz' test) is? It's pretty straightforward to verify the conditions that has to be met...

Umm, by , do you perhaps mean



You should have learned long ago that exponentials grow much faster than power functions.
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qleak
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PostPosted: Sat, 16 Apr 2005 14:48:23 UTC    Post subject: Reply with quote

I'll use the AST as shown below:

http://en.wikipedia.org/wiki/Alternating_series_test

Your series is


So all you need to do is show that


The limit is calc I material unless, of course, you're asked to show that its zero.
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Kungsman
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PostPosted: Sat, 16 Apr 2005 15:02:08 UTC    Post subject: Reply with quote

One way to show that



is to use the binomial theorem. We have



so



and perhaps you can say something about what happens to this last fraction when x gets bigger.
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Kungsman
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PostPosted: Sat, 16 Apr 2005 15:05:01 UTC    Post subject: Reply with quote

qleak wrote:
I'll use the AST as shown below:

http://en.wikipedia.org/wiki/Alternating_series_test

Your series is


So all you need to do is show that


The limit is calc I material unless, of course, you're asked to show that its zero.


I think it should be



at least if you read from the left to the right, which of course isn't the case in all countries, but common in english... Wink
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jinydu
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PostPosted: Sat, 16 Apr 2005 15:27:05 UTC    Post subject: Reply with quote

moonsenshi, don't you have anything more to say on the "estimating a p-series" thread?
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Marvin_M
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PostPosted: Sat, 16 Apr 2005 15:29:41 UTC    Post subject: Reply with quote

Don't forget that the alternating series test has a monotonicity condition as well.

Since only the tail determines convergence, we need to show that for some N,

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Kungsman
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PostPosted: Sat, 16 Apr 2005 15:31:27 UTC    Post subject: Reply with quote

Marvin_M wrote:
Don't forget that the alternating series test has a monotonicity condition as well.

Since only the tail determines convergence, we need to show that for some N,



I think we leave that for moonsenshi18 to prove.
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Marvin_M
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PostPosted: Sat, 16 Apr 2005 15:33:51 UTC    Post subject: Reply with quote

Kungsman wrote:
Marvin_M wrote:
Don't forget that the alternating series test has a monotonicity condition as well.

Since only the tail determines convergence, we need to show that for some N,



I think we leave that for moonsenshi18 to prove.


My thoughts exactly.

Edit: Of course I know that you know such a condition must be checked.

The comment was intended for moonsenshi18.
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Matt
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PostPosted: Sat, 16 Apr 2005 22:13:18 UTC    Post subject: Reply with quote

Kungsman wrote:
One way to show that



is to use the binomial theorem.

Or L'Hospital's Rule.
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Kungsman
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PostPosted: Sun, 17 Apr 2005 09:01:17 UTC    Post subject: Reply with quote

Matthew wrote:
Kungsman wrote:
One way to show that



is to use the binomial theorem.

Or L'Hospital's Rule.


Americans and their L'Hospital... Wink
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