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 Post subject: Physics/Chem: Electronic Configurations and EnergyPosted: Wed, 2 Nov 2005 17:49:54 UTC
 S.O.S. Oldtimer

Joined: Tue, 20 May 2003 20:19:56 UTC
Posts: 226
The absorption of light of frequency 1.16 x 1011 Hz is required for CO molecules to go from the lowest rotational energy level to the next highest rotational energy level. Determine the energy for this transition in kJ/mol. h = 6.626 x 10-34 J s

a. 7.69 x 10-23 kJ/mol
b. 949 kJ/mol
c. 46.3 kJ/mol
d. 0.0463 kJ/mol

E = hv
= (1.16*10^11 Hz)(6.626*10^-34 J*s)
= 7.686 *10^-23 J = 7.69*10^-26 kJ* (6.02*10^23 molecules/ 1 mol) = 0.04629 kJ/mol

Which of the following three sets consist of atoms or ions with the same electron configuration in the ground state?

I. O (2-), Ne, and Mg (2+)
II. Ni, Cu+, Zn 2+
III. Hg, Tl+, and Pb (2+)

a. all but (II)
b. all but (I)
c. all three sets
d. only (I)

For this, I am not sure of the question's wording. Must all three ions/atoms of each Roman numeral have the same electron configuration in the ground state or must at least one of each Roman numeral have the same electronic configuration? If it is the latter, wouldn't the correct choice be all three sets?

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Gracias for your time, patience, and input.

"Which is a kind of integrity, if you look on every exit being an entrance somewhere else."
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