 |
S.O.S. Mathematics CyberBoard
|
| View previous topic :: View next topic |
| Author |
Message |
Kashif S.O.S. Newbie
Joined: 14 Mar 2004 Posts: 3
|
Posted: Sun, 14 Mar 2004 11:39:20 UTC Post subject: coordinates of the stationary point |
|
|
Find the coordinates of the stationary point on the curve:
y=3^2x - 18 (3^x)
Thanks. |
|
| Back to top |
|
 |
Kwyjibo Member of the 'S.O.S. Math' Hall of Fame

Joined: 10 Feb 2004 Posts: 2458 Location: The Colbert Nation
|
Posted: Sun, 14 Mar 2004 15:26:40 UTC Post subject: Re: coordinates of the stationary point |
|
|
Hello, Kashif!
The stationary, or critical points of a function occur when the derivative
is zero. So let's set your derivative equal to zero and solve for x!
.
.
.
Here you can see that the only x value that makes this expression true
is 2, because when x gets larger than 2 the left side of this equation gets
larger then the right, and when x is less than 2, the right side is larger.
So our critical point is at x=2.
Now we plug this into our function, to obtain the y value.
So the critical point is at (2,-81).
You could use the first and second derivative tests to determine if this is
a maximum or minimum, but you should be asble to easily convince
yourself that it is a minimum.
-Kwyjibo _________________
 |
|
| Back to top |
|
 |
|
|
You cannot post new topics in this forum You cannot reply to topics in this forum You cannot edit your posts in this forum You cannot delete your posts in this forum You cannot vote in polls in this forum
|
|