The real number *x*=*a* is a root of the polynomial *f*(*x*) if and only if

When we see a graph of a polynomial, real roots are **x-intercepts** of the graph of

Let's look at an example:

The graph of the polynomial above intersects the *x*-axis at (or close to) *x*=-2, at (or close to) *x*=0 and at (or close to) *x*=1. Thus it has roots at (or close to) *x*=-2, at (or close to) *x*=0 and at (or close to) *x*=1.

The polynomial will also have linear factors (*x*+2), *x* and (*x*-1). Be careful: This does not determine the polynomial! It is **not true** that the picture above is the graph of (*x*+2)*x*(*x*-1); in fact, the picture shows the graph of *f*(*x*)=-.3(*x*+2)*x*(*x*-1).

Here is another example:

The graph of the polynomial above intersects the *x*-axis at *x*=-1, and at *x*=2. Thus it has roots at *x*=-1 and at *x*=2.

The polynomial will thus have linear factors (*x*+1), and (*x*-2). Be careful: This does not determine the polynomial! It is **not true** that the picture above is the graph of (*x*+1)(*x*-2); in fact, the picture shows the graph of . It is not even true that the number of real roots determines the degree of the polynomial. In fact, as you will see shortly, , a polynomial of degree 4, has indeed only the two real roots -1 and 2.

The roots of large degree polynomials can in general only be found by numerical methods. If you have a programmable or graphing calculator, it will most likely have a built-in program to find the roots of polynomials.

Here is an example, run on the software package *Mathematica*:
Find the roots of the polynomial

Using the "Solve" command, *Mathematica* lists approximations to the nine real roots as

Here is another example, run on *Mathematica*:
Find the roots of the polynomial

*Mathematica* lists approximations to the seven roots as

Only one of the roots is real, all the other six roots contain the symbol *i*, and are thus complex roots (more about those later on). Note that the complex roots show up "in pairs"!

Numerical programs usually find approximations to both real and complex roots.

**Numerical methods are error-prone, and will get false answers! They
are good for checking your algebraic answers; they also are a last resort if nothing else "works".**

How many real roots does the polynomial have?

How many complex roots does the polynomial have?

Do you need more help? Please post your question on our S.O.S. Mathematics CyberBoard.

Sun Jun 8 21:48:14 MDT 1997

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