BUILDING FRACTIONS: Problem 3

Rule 17:
To build a fraction is the reverse of reducing the fraction. Instead of searching for the 1 in a fraction so that you can reduce, you insert a 1 and build.

Problem 3:
Create a fraction equivalent to tex2html_wrap_inline40 that has a denominator of 50.

Answer:
The answer is the fraction tex2html_wrap_inline42 .

Solution:
This problem is a little difficult in that there is no integer you can multiply 20 with and come up with a product of 50. Therefore, let's reduce the fraction first. Reduce tex2html_wrap_inline40 .
tex2html_wrap_inline46 = tex2html_wrap_inline48.
[You can verify this with your calculator.] Recall that you can multiply any number by 1 without changing the value of the number. (Rule 6). Multiply the fraction tex2html_wrap_inline50 by 1. Recall that 1 has many forms, look for the form of 1 that will result in a denominator of 50.
Since 5 tex2html_wrap_inline52 10 = 50, use the fraction tex2html_wrap_inline54 as 1.
Now tex2html_wrap_inline56 can be written as tex2html_wrap_inline58 . The product is tex2html_wrap_inline42.
We have created a fraction with a denominator equal to 50 that is equivalent to the fraction tex2html_wrap_inline40 .

Check:
Now prove to yourself with your calculator that your answer is correct. Calculate 4 divided by 20 and calculate 10 divided by 50; both should yield the same answer. If you are correct, the answers are the same (equivalent) and you have successfully built a fraction.

[Previous Problem] [Next Problem] [Menu Back]

S.O.S MATHematics home page

Do you need more help? Please post your question on our S.O.S. Mathematics CyberBoard.

Author:Nancy Marcus

Copyright 1999-2017 MathMedics, LLC. All rights reserved.
Contact us
Math Medics, LLC. - P.O. Box 12395 - El Paso TX 79913 - USA
users online during the last hour