Note:
Problem 2.4b:
Answer:
Solution:
First make a note of the fact that you cannot take the square root of a
negative number. The term is valid only if and the term is valid if . The restricted domain must satisfy both of these
constraints. Therefore, the domain is the set of real numbers
Isolate the term.
The graph represents the right side of the original equation minus the left
side of the original equation.. The x-intercept(s) of this graph is(are) the
solution(s). Since the only x-intercept is 15.95, we have verified that
the only solution is 15.95.
If you would like to return to the problem page, click on Problem.
If you would like to go back to the equation table of contents, click
on Contents.
Do you need more help? Please post your question on our
S.O.S. Mathematics CyberBoard.
Since is already isolated, we square both sides of the
equation.
Square both sides of the equation.
Solve for x using the quadratic formula.
There are two approximate (rounded) answers: x = 15.95,
Check the solution 15.95 by substituting 15.95 in the original equation
for x. If the left side of the equation equals the right side of the
equation after the substitution, you have found the correct answer.
Since the left side of the original equation equals the right side of the
original equation after we substituted our solution for x, we have verified
that the solutions is x=15.95.
Check the solution 7.22 by substituting 7.22 in the original equation
for x. If the left side of the equation equals the right side of the
equation after the substitution, you have found the correct answer.
Since the left side of the original equation does not equal the right side
of the original equation after we substituted our solution for x, the
x=7.22 is not valid.
You can also check the answer by graphing the equation:
If you would like to review the solution for problem 2.4c, click on Solution.
Contact us
Math Medics, LLC. - P.O. Box 12395 - El Paso TX 79913 - USA
users online during the last hour