EQUATIONS CONTAINING VARIABLES UNDER ONE OR MORE RADICALS

• In order to solve for x, you must isolate x.
• In order to isolate x, you must remove it from under the radical.
• If there are three radicals in the equation, isolate one of the radicals.
• Then raise both sides of the equation to a power equal to the index of the isolated radical.
• Isolate the remaining radical.
• Raise both sides of the equation to a power equal to the index of the isolated radical.
• You should now have a polynomial equation. Solve it.
• Remember that you did not start out with a polynomial; therefore, there may be extraneous solutions. Therefore, you must check your answers.

Example 2:

First make a note of the fact that you cannot take the square root of a negative number. Therefore, the term is valid only if the second term is valid if , and the term is valid only if The equation is valid if all three terms are valid, therefore the domain is restricted to the common domain of the three terms or the set of real numbers

Multiply both sides of the equation by 3 to remove the fraction.

Square both sides of the equation and simplify.

Isolate the term and simplify.

Square both sides of the equation and simplify.

Use the quadratic formula to solve for x.

The answers are

Check the solution by substituting 5 in the original equation for x. If the left side of the equation equals the right side of the equation after the substitution, you have found the correct answer.

• Left Side:

• Right Side:

Since the left side of the original equation equals the right side of the original equation after we substituted 5 for x, then x=5 is a solution.

Check the solution by substituting 0.155505 in the original equation for x. If the left side of the equation equals the right side of the equation after the substitution, you have found the correct answer.

• Left Side:

  

• Right Side:

Since the left side of the original equation does not equal the right side of the original equation after we substituted 0.155505 for x, then the solution x=0.155505 is a not valid and not a solution after all.

You can also check the answer by graphing the equation:

The graph represents the right side of the original equation minus the left side of the original equation. The x-intercept(s) of this graph is(are) the solution(s). Since there is just one x-intercept at 5, then the only solution is x=5.

If you would like to review another example, click on Example

If you would like to test yourself by working some problems similar to this example, click on Problem.

If you would like to go back to the equation table of contents, click on Contents.

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