If you would like an in-depth review of fractions, click on Fractions.

Solve for x in the following equation.

Problem 5.5 a:         $\displaystyle \frac{3}{x^{2}-5x+9}+\displaystyle \frac{2}{5}=x-3$

Answer:     $x=4\bigskip\bigskip $

Simplify the equation by subtracting $\displaystyle \frac{2}{5}$ from both sides of the equation.

\begin{eqnarray*}&& \\
\displaystyle \frac{3}{x^{2}-5x+9} &=&x-\displaystyle \f...
...yle \frac{3}{x^{2}-5x+9} &=&\displaystyle \frac{5x-17}{5} \\

Multiply both sides of the equation by an expression that represents the lowest common denominator. The expression $\left( x^{2}-5x+9\right) \left(
5\right) $ is the smallest expression because it is the smallest expression that is divisible by all the denominators.

\begin{eqnarray*}&& \\
\displaystyle \frac{3}{x^{2}-5x+9} &=&\displaystyle \fra...
...eft( x-4\right) \left( 5x^{2}-22x+42\right) \\
&& \\
&& \\

The only way a product can equal zero is if at least one of the factors equals zero.

\begin{eqnarray*}&& \\
If\ x-4 &=&0,\ then\ x=4 \\
&& \\
If\ 5x^{2}-22x+42 &=...
...hen\ x=\displaystyle \frac{22\pm \sqrt{-356}}{10}. \\
&& \\

$x=\displaystyle \frac{22\pm \sqrt{-356}}{10}$ are not real numbers. Therefore, there is only one real answer x=4.

Check the answer in the original equation.

Check the solution x=4 by substituting 4 in the original equation for x. If the left side of the equation equals the right side of the equation after the substitution, you have found the correct answer.

Left Side: $\qquad \displaystyle \frac{3}{x^{2}-5x+9}+\displaystyle \frac{2}{5}=\displaysty...
...\displaystyle \frac{2}{5}=\displaystyle \frac{3}{5}+\displaystyle \frac{2}{5}=1$

Right Side: $\qquad x-3=4-3=1$.

Since the left side of the original equation is not equal to the right side of the original equation after we substitute the value 4 for x, then x=4is a solution.

You can also check your answer by graphing

\begin{eqnarray*}&& \\
f(x) &=&\displaystyle \frac{3}{x^{2}-5x+9}+\displaystyle \frac{2}{5}-x+3 \\

(formed by subtracting the right side of the original equation from the left side). Look to see where the graph crosses the x-axis; that will be the real solution. Note that the graph crosses the x-axis at one spot,

This means that there is one real solution and the solution is x=4.

If you would like to test yourself by working some problems similar to this example, click on problem.

If you would like to go back to the equation table of contents, click on Contents

[Algebra] [Trigonometry]
[Geometry] [Differential Equations]
[Calculus] [Complex Variables] [Matrix Algebra]

S.O.S MATHematics home page

Do you need more help? Please post your question on our S.O.S. Mathematics CyberBoard.

Author: Nancy Marcus

Copyright 1999-2019 MathMedics, LLC. All rights reserved.
Contact us
Math Medics, LLC. - P.O. Box 12395 - El Paso TX 79913 - USA
users online during the last hour