If you would like an review of trigonometry, click on trigonometry.
Solve for x in the following equation.
There are an infinite number of solutions to this problem. To solve for x, you must first isolate the sine term.
If we restriction the domain of the sine function to , we can use the inverse sine function to solve for reference angle and then x.
We know that the e function is positive in the first and the second quadrant. Therefore two of the solutions are the angle that terminates in the first quadrant and the angle that terminates in the second quadrant. We have already solved for
The exact solutions are and
The period of the sin function is This means that the values will repeat every radians in both directions. Therefore, the exact solutions are and where n is an integer.
The approximate solutions are and where n is an integer.
These solutions may or may not be the answers to the original problem. You much check them, either numerically or graphically, with the original equation.
Check the answer x=1.92198387248
Since the left side equals the right side when you substitute 1.92198387248for x, then 1.92198387248 is a solution.
Check the answer x=13.7859793955
Since the left side equals the right side when you substitute 13.7859793955for x, then 13.7859793955 is a solution.
Graph the equation
Note that the graph crosses the x-axis many times indicating many solutions. Note that it crosses at 1.92198387248.
Since the period is it crosses again at 1.92198387248 + 31.415927 = 33.3379104084 and at 1.92198387248 + 2( 31.415927 ) = 64.753838 , etc. The graph crosses at 13.7859793955 . Since the period is , it will cross again at 13.7859793955 + ( 31.415927 ) = 45.201906 and at 13.7859793955 + 2( 31.415927) = 76.617833, etc
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