Problems on Techniques of Integration

Since

\begin{displaymath}\frac{3x^2 - 2x+1}{2x - 1} = \frac{3}{2} x - \frac{1}{4}+ \frac{3}{4} \frac{1}{(2x - 1)},\end{displaymath}

We have

\begin{displaymath}\int \frac{3x^2 - 2x+1}{2x - 1}dx = \frac{3}{4} x^2 - \frac{1}{4}x+ \frac{3}{8}\ln\vert 2x-1\vert+ C\;.\end{displaymath}

Detailed Answer.


If you prefer to jump to the next problem, click on Next Problem below.

[Next Problem] [Matrix Algebra]
[Trigonometry] [Calculus]
[Geometry] [Algebra]
[Differential Equations] [Complex Variables]

S.O.S MATHematics home page

Do you need more help? Please post your question on our S.O.S. Mathematics CyberBoard.

Mohamed A. Khamsi

Copyright 1999-2017 MathMedics, LLC. All rights reserved.
Contact us
Math Medics, LLC. - P.O. Box 12395 - El Paso TX 79913 - USA
users online during the last hour