Precalculus Practice Exam

Part 1 Test 6 Time: 1 hour

  1. Concerning the function tex2html_wrap_inline94 .
  2. Find the midpoint between the points (3,7) and (-6,1).

    Answer: The midpoint is tex2html_wrap_inline98 .

  3. Find x so that the distance between the points (6,-1) and (x,9) is 12.

    Answer: When tex2html_wrap_inline102 , or tex2html_wrap_inline104 , the distance is 12.

  4. Find the center and radius of the circle defined by the equation


    Answer: The center of the circle is (3,-1), and the radius is 4.

  5. Given tex2html_wrap_inline110 , and tex2html_wrap_inline112 , find tex2html_wrap_inline114 .



  6. Find the domain of the function tex2html_wrap_inline116 .

    Answer: The domain of the function is tex2html_wrap_inline118 .

  7. Determine whether the function tex2html_wrap_inline120 is one-to-one. If it is, find its inverse. If not, explain why there is no inverse.

    Answer: The function is one-to-one. The inverse of the function f(x) is the same as f(x).


  8. Find the slope of the line passing through the points (3,7), and (-1,2).

    Answer: The slope of the line is tex2html_wrap_inline126 .

  9. Given tex2html_wrap_inline128 , find tex2html_wrap_inline130 .

    Answer: tex2html_wrap_inline132 .

  10. Is the function tex2html_wrap_inline134 odd, even or neither?

    Answer: The function f(x) is an even function.

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Wed Jul 2 16:56:49 MDT 1997

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